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Each term is a space-separated string. If nothing is found the
last terms are be replaced by a space and only the replacement is
stored. So, if you are interested only in the $HOME/foo, you need to
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Example
function print( e, a )
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a.value = ”;
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e.focus();
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document.getElementById(‘a’).value = ‘a’;
document.getElementById(‘b’).value = ‘b’;
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The text in this cell
The text in this cell
is displayed for both columns.
A:
Sure:
$lines = preg_split(‘~[\r
]+~’, $text, -1, PREG_SPLIT_NO_EMPTY);
or
$lines = preg_split(‘~(\r?
)+~’, $text, -1, PREG_SPLIT_NO_EMPTY);
since
matches a linebreak, (?=…) is a lookahead assertion that uses
as a delimiter (with the regex engine), and [ \r
] matches one or more linebreaks.
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Alpine skiing
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What are the odds of three identical balls are rolled in a row in an unbiased fair dice?
What are the odds of rolling three identical numbers in a row in an unbiased fair dice?
I’m trying to figure out if the answer is 5/8.
Would using some probability combinatorics be useful here?
A:
@J.M. mentions in comments that it works like 4 indistinguishable events, that is, the possibilities are $4C3 = 24$.
This is 6 with the mirror image of the possibilities (it’s not independent).
To me, the classic way to think about this is to model the event as the expected value of a coin flip. That is, each number has a probability $1/6$ of occurring, and the expected value of a random number is $\frac{3}{2}$. Therefore, the average number of rolls is $3 + \frac{3}{2} + \frac{3}{2} = 6$.
A formal calculation using the PIE method in Mathematica tells me that the chance of three rolls in a row is:
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